The vertices of the pentagon ABCDE are A(0,4), B(4,0), C(3,- 4), D(-3,- 4), E(-4,0). If the pentagon is translated 5 units down and 4units right, the new vertices are:a. A'(4, -1), B'(8,-5), C'(7,-9), D'(1,-9), E'(0,-5)b. A'(4, -1), B'(8,-5), C'(7,-9), D'(1,-9), E'(1,-5)C. A'(4, -1), B'(5,-5), C'(7,-9), D'(1,-9), E'(0,-5)d. A'(4, -1), B'(8,-5), C'(7.-9), D'(0,-9), E'(0,-5)
Accepted Solution
A:
Answer:The answer to your question is: a. A'(4, -1), B'(8,-5), C'(7,-9), D'(1,-9), E'(0,-5)Step-by-step explanation:pentagon ABCDETranslated 5 units down and 4 units right Changes Final VerticesA (0 , 4) A (0 + 4 , 4 - 5) A (4, -1)B (4 , 0) B (4 + 4, 0 - 5) B (8, -5)C (3 , - 4) C (3 + 4, - 4 - 5) C (7, -9)D (-3 , - 4) D (-3 + 4, - 4- 5) D (1, -9)E (-4 , 0) E (-4 + 4, 0 - 5) E (0, -5)