MATH SOLVE

4 months ago

Q:
# identify whether each equation has no solution, one solution, or infinitely many solutions. 1. 4x−x=2x+x2. 2x+1=53. 4x+2=5x−x+44. 2(x+4)=4(x+2)

Accepted Solution

A:

Answer:infinitely manyone solutionno solutionone solutionStep-by-step explanation:1. 4x−x=2x+xSimplifies to 3x = 3x, which is true for all values of x. Hence there are infinitely many solutions.___2. 2x+1=5True only for x=2; one solution.___3. 4x+2=5x−x+4Simplifies to ... 4x +2 = 4x +4 2 = 4 . . . . . . . not true for any value of x; no solution.___4. 2(x+4)=4(x+2)Simplifies to ... 2x +8 = 4x +8 0= 2x . . . . . . . . . subtract 2x+8True only for x=0; one solution.