MATH SOLVE

4 months ago

Q:
# Find a number less than 100 that is increased by one-fifth of its value when its digits are reversed.

Accepted Solution

A:

Lets say the number is ab. Its value is 10a + b
When it is reversed it is 10b + a = 12a+1.2b (from the condition its value should increase 0.2 times).
11 a = 8.8b
a/b = 8.8/11 = 0.8/1 = 8/10 = 4/5 ( we do this because a and b should be natural numbers less than 10).
answer is 45.