Where is the vertex of the parabola?y = x2 + 2x + 3A.above the x-axisB.on the x-axisC.on the y-axisD.below the x-axis

Answer:ABOVE the x-axisStep-by-step explanation:Please use "^" to denote exponentiation:  y = x^2 + 2x + 3To find the vertex, we must complete the square of y = x^2 + 2x + 3, so that we have an equivalent equation in the form f(x) = (x - h)^2 + k.Starting with  y = x^2 + 2x + 3,we identify the coefficient of x (which is 2), take half of that (which givesus 1),  add 1 and then subtract 1, between "2x" and "3":y = x^2 + 2x + 1 - 1 + 3Now rewrite x^2 + 2x + 1 as (x + 1)^2:y = (x + 1)^2 - 1 + 3, or y = (x + 1)^2 + 2.  Comparing this to f(x) = (x - h)^2 + k, we see that h = 1 and k = 2.  This tells us that the vertex of this parabola is at (h, k):  (1, 2), which is ABOVE the x-axis.